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9.81x^2+2x-6=0
a = 9.81; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·9.81·(-6)
Δ = 239.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{239.44}}{2*9.81}=\frac{-2-\sqrt{239.44}}{19.62} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{239.44}}{2*9.81}=\frac{-2+\sqrt{239.44}}{19.62} $
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